Sample I has higher O18/O16 ratio of atoms as compared to Sample II. The average mass of oxygen in Sample I is _____ that of Sample II :
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The O18/O16 ratio indicates the relative abundance of the heavier oxygen-18 isotope. A higher ratio means Sample I has a greater proportion of O18 atoms compared to O16. Since O18 has a greater mass (approximately 18 u) than O16 (approximately 16 u), a sample with a higher proportion of the heavier isotope will have a higher average atomic mass. Therefore, the average mass of oxygen in Sample I is greater than that of Sample II.
Final Answer: greater than