sec210º – cot280º = ?

Foundation

Mathematics Foundation

Introduction to Trigonometry

Question

sec²10º – cot²80º = ?

A

$\frac{1}{2}$

B

$\frac{3}{2}$

C

1

D

0

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sec²10º – cot²80º = sec²10º – cot²(90º – 10º) = sec²10º – tan²10º = 1.