Foundation
Mathematics Foundation
Properties of Real Number
Rational Numbers
Playing with Numbers
Question
Show that every positive even integer is of the form 2q and every positive odd integer is of the form 2q+1, where q is a whole number.
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Solution
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(i) Let 'a' be an even positive integer. 
Apply division algorithm with a and b, where b=2 
a=(2×q)+r where 0\le r < 2
 a=2q+r where r=0 or r=1
since 'a' is an even positive integer, 2 divides 'a'. 
r=0a=2q+0=2q
Hence, a=2q when 'a' is an even positive integer. 
(ii) Let 'a' be an odd positive integer. 
apply division algorithm with a and b, where b=2
a=(2×q)+r where 0\le r < 2 
a=2q+r where r=0 or 1 
Here r0 (a is not even) r=1
a=2q+1
Hence, a=2q+1 when 'a' is an odd positive integer.