Engineering
Physics
Newtons Second Law of Motion
Center of Mass
Momentum and Energy Conservation for System of Particles
Question

Shown in the figure is a system of three particles having masses m1 = 1kg, m2 = 2kg and m3 = 4 kg respectively connected by two springs. The acceleration of A, B and C at any instant are 1m/sec2, 2m/sec2 and 1/2 m/sec2 respectively directed as shown in the figure. The external force in N acting on the system is………….

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Solution
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The acceleration of center of mass of the

system     =acm=m1a1+m2a2+m3a3m1+m2+m3

⇒     The net force acting on the system =  (m1+m2+m3)a¯cm

⇒     Fnet = (m1a1 + m2a2 – m3a3)

=(1)(1)+(2)(2)12(4)N=3N