Foundation
Mathematics Foundation
Introduction to Trigonometry
Question
tan 10º tan 15º tan 75º tan 80º = ?
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Solution
Given expression = (tan 10º tan 80º) (tan 15º tan 75º)
= {tan 10º tan (90º – 10º)} {tan 15º tan (90º – 15º)}
= (tan 10º cot 10º) (tan 15º cot 15º) = 1 × 1 = 1.
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