Foundation
Mathematics Foundation
nth term of AP
Question

The 17th term of an AP exceeds its 10th term by 21. The common difference of the AP is

3

– 2

2

– 3

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Solution

(T17 – T10) = 21 ⇒ (a + 16d) – (a + 9d) = 21 ⇒ 4d = 21 ⇒ d = 3.