The 5th term of an AP is 20 and the sum of its 7th and 11th terms is 64. The common difference of the AP is
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T5 = 20 ⇒ a + 4d = 20. ....(i)
(T7 + T11) = 64 ⇒ (a + 6d) + (a + 10d) = 64 ⇒ a + 8d = 32. ....(ii)
On Solving (i) and (ii), we get d = 3.