The area (in square units) bounded by the curves y = \sqrt{x}, 2y – x + 3 = 0, x‑axis and lying in the first quadrant is :

Engineering

Mathematics

Introduction to Area

Question

The area (in square units) bounded by the curves $y = \sqrt{x}$ , 2y – x + 3 = 0, x‑axis and lying in the first quadrant is :

$\frac{27}{4}$

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Required area $= \int_{0}^{9} \sqrt{x} dx - \frac{1}{2} \times 6 \times 3 = 9$ square units.