The atomic masses of He and Ne are 4 and 20 a.m.u., respectively. The value of the de Broglie wavelength of He gas at –73°C is “M” times that of the de Broglie wavelength of Ne at 727°C. M is

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$λ = \frac{h}{mV} ∴ = λα \frac{1}{\sqrt{TM}}$

$\Rightarrow \frac{λ_{Ne}}{λ_{He}} = \frac{\sqrt{1200 \times 4}}{\sqrt{1000 \times 20}}$

$\Rightarrow λ$ _He = 5 $λ$ _Ne

$∴$ M = 5

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