The average molecular mass of a mixture of O2 and O3 gases is 40. It represents that the mixture contains :

Engineering

Chemistry

Average Atomic and Molecular Masses

Question

The average molecular mass of a mixture of O₂ and O₃ gases is 40. It represents that the mixture contains :

60% O₃, by mass

50% O₃, by moles

40% O₃, by mass

50% O₃, by mass

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32x + 48(1 – x) = 40

4x + 6(1 – x) = 5

– 2x + 6 = 5

x = 1/2

mole percent of O₃ = 50%,

mass percent = $\frac{48 \times 1}{48 \times 1 + 32 \times 1} \times 100$ = $\frac{48}{80} \times 100$ = 60 percent O₃ by mass.