Engineering
Mathematics
Intercept from a Circle
Question

The circle passing through the point (–1, 0) and touching the y‑axis at (0, 2) also passes through the point

(–4, 0)

 (32,  0)

 (32,  52)

 (52,  2)

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Solution

  (h – 0)2 + (2 – 2)2 = (h + 1)2 + (2 – 0)2

h2 = h2 + 1 + 2h +4

 h=52

Equation of circle is

 (x+52)2+(y2)2=(520)2                

 x2+254+5x+y2+44y=254

x2 +y2 + 5x – 4y + 4 = 0

from given points only point (–4, 0) satisfies this equation.

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