The common oxidation state of oxygen is –2. This is best explained as due to-

Foundation

Chemistry Foundation

Oxidation Number

Question

2 electrons in the outermost shell

4 electrons in the outermost shell

6 electrons in the outermost shell

8 electrons in the outermost shell

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₈O = 2,6. this explains that to achive nearest inert gas configuration, oxygen gains 2 electrons. so, its common oxidation state is - 2.

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