The container carrying some liquid shown in the diagram is given some small acceleration \overset{\rightarrow}{a}.

Engineering

Physics

Liquid Pressure

Buoyancy

BernoulIis Equation and Equation of Continuity

Question

The container carrying some liquid shown in the diagram is given some small acceleration $\vec{a}$ .

If $\vec{a}$ is directed towards left , P_A – P_B remain same

If $\vec{a}$ is directed towards right, P_A – P_B decreases

If $\vec{a}$ is directed upwards, P_A – P_B increases

If $\vec{a}$ is directed down wards, P_A – P_B remain same

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When a liquid container accelerates, the pressure difference between two points at the same horizontal level depends on the horizontal acceleration component. Points A and B are at the same height. The pressure difference P_A - P_B is given by ρ * a_x * L, where ρ is density, a_x is horizontal acceleration, and L is horizontal distance between A and B.

If acceleration is purely vertical (up or down), the horizontal component a_x is zero, so P_A - P_B remains the same as when at rest. If acceleration is horizontal (left or right), a_x is non-zero, changing the pressure difference.

Final Answer: If $\vec{a}$ is directed downwards, P_A – P_B remains same.