The degree of dissociation (α) of a weak electrolyte AxBy is related to van't Hoff factor (i) by the expression

Engineering

Chemistry

Relative Lowering in Vapour Pressure

Question

The degree of dissociation (α) of a weak electrolyte A_xB_y is related to van't Hoff factor (i) by the expression

$α = \frac{i - 1}{(x + y - 1)}$

$α = \frac{x + y + 1}{i - 1}$

$α = \frac{x + y - 1}{i - 1}$

$α = \frac{i - 1}{x + y + 1}$

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A_xB_y —→ xA^y+ + yB^x–

1 – α xα yα

i = 1 – α + xα + yα

i = 1 + α(x + y – 1)

$α = \frac{i - 1}{(x + y - 1)}$