The density of a solution prepared by dissolving 120 g of urea (mol. mass = 60 u) in 1000 g of water is 1.15 g/mL. The molarity of this solution is :

Engineering

Chemistry

Concentration Terms

Question

0.50 M

1.02 M

2.05 M

1.78 M

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Molarity $= \frac{n_{solute}}{V_{solution}} = \frac{120 / 60}{(1000 + 120) / 1 .15} \times 1000 \approx 2 .05 M$

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