Engineering
Mathematics
Introduction to Determinants
Question

The determinant Δ=a2+x2abacabb2+x2bcacbcc2+x2 is divisible by

x

x2

x3

x4

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Solution
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Δ=a2+x2abacabb2+x2bcacbcc2+x2
Expanding it,
= (a2 + x2)(x2)(b2 + c2 + x2) – ab(abx2) + ac(– acx2)
= x2(a2b2 + a2c2 + a2x2 + x2b2 + x2c2 + x4 – a2b2 – a2c2)
= x2(a2x2 + x2b2 + x2c2 + x4)
= x4(a2 + b2 + c2 + x2)
So it is divisible by x, x2, x3 and x4
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