The diffusion coefficient of an ideal gas is proportional to its mean free path and mean speed. The absolute temperature of an ideal gas is increased 4 times and its pressure is increased 2 times, As a result, the diffusion coefficient of this gas increases x times. the value of x is

Engineering

Chemistry

Collision Frequency and Mean Free Path

Question

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$λ = \frac{1}{\sqrt{2} {πσ}^{2} . N^{*}}$

$D . C . α \frac{u_{avg .}}{\sqrt{2} {πσ}^{2} . N^{*}}$

$N_{0} = \frac{P}{KT}$

$U_{avg} α \sqrt{T}$

$D . C . α \frac{T^{3 / 2}}{P}$

$\frac{D . C_{2}}{D . C_{1}} = \frac{4 \times \sqrt{4}}{2} = \frac{8}{2} = 4$