Engineering
Mathematics
Plane and Its Different Forms
Question

The equation of the plane containing the line 2x – 5y + z = 3; x + y + 4z = 5, and parallel to the plane, x + 3y + 6z = 1, is

2x + 6y + 12z = 13

x + 3y + 6z = 7

2x + 6y + 12z = –13

x + 3y + 6z = –7

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Solution

Putting  z = 0, get   x = 4, y = 1

 (4, 1, 0)

Required plane is

1·(x – 4) + 3(y – 1) + 6(z – 0) = 0

x + 3y + 6z = 7