The equation of the plane containing the line 2x – 5y + z = 3; x + y + 4z = 5, and parallel to the plane, x + 3y + 6z = 1, is
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Putting z = 0, get x = 4, y = 1
(4, 1, 0)
Required plane is
1·(x – 4) + 3(y – 1) + 6(z – 0) = 0
x + 3y + 6z = 7