The figure shows a square loop L of side 5 cm which is connected to a network of resistances. The whole setup is moving towards right with a constant speed of 1 cms–1. At some instant, a part of L is in a uniform magnetic field of 1T, perpendicular to the plane of the loop. If the resistance of loop is 1.7 Ω, the current in the loop at that instant will be close to :

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The figure shows a square loop L of side 5 cm which is connected to a network of resistances. The whole setup is moving towards right with a constant speed of 1 cms^–1. At some instant, a part of L is in a uniform magnetic field of 1T, perpendicular to the plane of the loop. If the resistance of loop is 1.7 Ω, the current in the loop at that instant will be close to :

115 µA

170 µA

60 µA

150 µA

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Since it is a balanced wheatstone bridge, its equivalent resistance $= \frac{4}{3} Ω$

ε = Bℓv = 5 × 10^–4 V

So total resistance

$E = \frac{4}{3} + 1 .7 \approx 3 Ω$

$∴ i = \frac{ε}{R} \approx 166 μA \approx 170 μA$