The first ionisation potential of Na is 5.1 eV. The value of electron gain enthalpy of Na+ will be:

Engineering

Chemistry

Degree of Freedom Heat Capacities

Question

The first ionisation potential of Na is 5.1 eV. The value of electron gain enthalpy of Na⁺ will be:

–10.2 eV

–5.1 eV

–2.55 eV

+2.55 eV

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

Na(g) + 5.1 eV $\to_{}^{}$ Na⁺(g) + e¯

$∴$ Ionisation energy of Na = – $∆$ Heg of Na⁺

Na $\to_{}^{}$ Na⁺ + e¯ $∆$ H = 5.1 eV

Na⁺ + e¯ $\to_{}^{}$ Na $∆$ H = – 5.1 eV

Please subscribe our Youtube channel to unlock this solution.