The following reaction is performed at 298 K.2NO(g) + O2(g) ⇌ 2NO2(g)The standard free energy of formation of NO(g) is 86.6 kJ/mol at 298 K. What is the standard free energy of formation of NO2(g) at 298 K? (Kp = 1.6×1012)

Engineering

Chemistry

Cell Potential Free Energy and Equilibrium Constant

Question

The following reaction is performed at 298 K.

2NO(g) + O₂(g) ⇌ 2NO₂(g)

The standard free energy of formation of NO(g) is 86.6 kJ/mol at 298 K. What is the standard free energy of formation of NO₂(g) at 298 K? (K_p = 1.6×10¹²)

$86600 - \frac{ℓn (1 .6 \times 10^{12})}{R (298)}$

R(298) ℓn(1.6 × 10¹²) – 86600

0.5[2 × 86,600 – R(298) ℓn(1.6 × 10¹²)]

86600 + R(298) ℓn(1.6 × 10¹²)

LiveFree JEE Main Previous Year Online Papers Live Free JEE Advance Previous Year Online Papers

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

2NO(g) + O₂(g) ⇌ 2NO₂(g)

$ΔG ° = 2 Δ_{f} G º ({NO}_{2}) - Δ_{f} G ° (O_{2}) - 2 Δ_{f} G ° (NO)$

= – RT ℓn K

$Δ_{f} G ° ({NO}_{2}) = \frac{1}{2} (2 \times 86600 - R \times 298 ℓn (1 .6 \times 10^{12}))$