Engineering
Mathematics
Plane and Its Different Forms
Distance from a Plane
Question

The foot of the perpendicular from the point A(7,14,5) to the plane 2x + 4y − z = 2 is?

(3,1,8)

(1,2,8)

(3,−3,5)

(5,−3,−4)

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Solution
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Let N be the foot of the perpendicular drawn from the point A(7,14,5) and perpendicular to the plane 2x + 4y − z = 2

Then, the equation of the line PN is x72=y144=z51=λ (say)

Let the coordinates of N be N(2λ + 7,4λ + 14, −λ + 5)

Since N lies on the plane 2x + 4y − z = 2, so

2(2λ + 7) + 4(4λ + 14) − (−λ + 5) = 2

⇒ 21λ = −63
⇒λ = −3

∴ required foot of the perpendicular is

N(−6 + 7, −12 + 14, 3 + 5), i.e., N(1,2,8).