The freezing point (in °C) of a solution containing 0.1 g of K3[Fe(CN)6] (Mol. Wt. 329) in 100 g of water (Kf = 1.86 K kg mol

Engineering

Chemistry

Intensive Extensive State and Path Function

Question

The freezing point (in °C) of a solution containing 0.1 g of K₃[Fe(CN)₆] (Mol. Wt. 329) in 100 g of water (K_f = 1.86 K kg mol^–1) is

–5.7 × 10^–2

–1.2 × 10^–2

–2.3 × 10^–2

–5.7 × 10^–3

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$∆$ T = k_f × m × i × 1000

$= 1.86 \times \frac{0.1}{329 \times 100} \times 4 \times 1000$

= 2.26 × 10^–2 $\approx$ 2.3 × 10^–2

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