Foundation
Mathematics Foundation
HCF and LCM
Properties of Real Number
Linear Equations in One Variable
Question

The H.C.F. of the numbers 16.5,0.90 and 15 is

15

0.90

0.3

16.5

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Solution
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The given numbers are 16.5,0.90 and 15
Multiplying each number by 100 we get 1650,90 and 1500
Let us consider the numbers 1650,90 and 1500

By prime factorization, we get,

1650 = 2 × 3 × 5× 11
90 = 2 × 3× 5
1500 = 2× 3 × 53
H.C.F. of 1650.90 and 1500 is 2 × 3 × 5 = 30
Therefore, H.C.F. of 16.5,0.90 and 15 will be 30100= 0.30
So, option D is correct.