The height (in cm) risen by a liquid in a capillary tube having diameter of its bore as 1 mm is given by: (Take S = 0.075 N/m, density = 1 gm/cc, contact angle = 0°)

Engineering

Physics

Capillary and Pressure Difference due to Surface Tension

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$R = \frac{2 Scosθ}{rρg} = \frac{4 Scosθ}{dρg} = \frac{4 \times 0.075}{10^{- 3} \times 10^{3} \times 10} = \frac{0.3}{10} m = 3 cm$