The hybridisation of orbitals of N atom in NO3–, NO2+ and NH4+ are respectively

Engineering

Chemistry

Hybridisation

Question

The hybridisation of orbitals of N atom in NO₃^–, NO₂⁺ and NH₄⁺ are respectively

sp², sp³, sp

sp², sp, sp³

sp, sp³, sp²

sp, sp², sp³

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${NO}_{2}^{+}$ Number of electron pairs = 2 Number of bond pairs = 2 Number of lone pair = 0 So, the species is linear with sp hybridisation

${NO}_{3}^{-}$ Number of electron pairs = 3 Number of bond pairs = 3 Number of lone pair = 0 So, the species is trigonal planar with sp² hybridisation.

${NH}_{4}^{+}$ Number of electron pairs = 4 Number of bond pairs = 4 Number of lone pair = 0 So, the species is tetrahedral with sp³ hybridisation.