The incorrect match in the following is :

Engineering

Chemistry

Gibbs Free Energy Calculations and Third Law

Gibbs Free Energy and Equilibrium

Question

The incorrect match in the following is :

ΔG⁰ > 0, K < 1

ΔG⁰ < 0, K > 1

ΔG⁰ < 0, K < 1

ΔG⁰ = 0, K = 1

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ΔG = ΔGº + RTlnθ₁

at equil. ΔG = 0

ΔGº = –2.303 RT log K

if ΔGº < 0

⇒ –2.303RT log K < 0

⇒ log K > 0

⇒ K > 1