The integral ∫24logx2logx2+log(36−12x+x2)dx is equal to
2
1
4
6
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Let I=∫24ℓogx2ℓogx2+ℓog(x−6)2dx ......... (A)
Also, I=∫24log(x−6)2log(x−6)2+logx2dx......(B) (using king property)
∴ (A)+(B)⇒2I=∫241 dx⇒I=22=1.