The length of the diameter of the circle which touches the x‑axis at the point (1, 0) and passes through the point (2, 3) is :

Engineering

Mathematics

Intercept from a Circle

Question

$\frac{10}{3}$

$\frac{6}{5}$

$\frac{3}{5}$

$\frac{5}{3}$

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

(x – h)² + (y – k)² = k²

Centre (h, k), Radius = k

(1 – h)² + k² = k² } $\to h = 1; k = \frac{5}{3}$

Radius $= \frac{5}{3}$ . Diameter $= \frac{10}{3}$ .