The lines px + qy + r = 0, qx + ry + p = 0 and rx + py + q = 0 are concurrent then
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p(rq – p2) – q(q2 – rp) + r(qp – r2) = 0
3pqr – p3 – q3 – r3 = 0
p3 + q3 + r3 = 3pqr
p3 + q3 + r3 – 3pqr = 0
(p + q + r)(p2 + q2 + r2 – pq – qr – pr) = 0
⇒ p + q + r = 0 or
p2 + q2 + r2 – pq – qr – pr = 0
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