This reaction involves the addition of HBr to an alkene. The key concept here is Markovnikov's Rule, which states that in the addition of a protic acid (like HBr) to an unsymmetrical alkene, the hydrogen atom adds to the carbon with the greater number of hydrogen atoms, and the halide adds to the carbon with fewer hydrogen atoms.

Let's analyze the given alkene structure. The molecule is 1-methylcyclohex-1-ene. The double bond is between carbon 1 (which has one hydrogen and is attached to the ring and a methyl group) and carbon 2 (which has two hydrogens). According to Markovnikov's rule, the hydrogen from HBr will add to carbon 2 (the less substituted carbon), and the bromine will add to carbon 1 (the more substituted, tertiary carbon).

Therefore, the major product will be 1-bromo-1-methylcyclohexane.

The chemical equation for this reaction is:

C H_{3} - C_{6} H_{9} + H B r \to C H_{3} - C B r - C_{6} H_{11}

Related Topics & Formulae:

Markovnikov's Rule: A rule used to predict the regiochemistry of electrophilic addition reactions of alkenes and alkynes. It states that the electrophile adds to the carbon with the most hydrogen atoms.

Electrophilic Addition: A reaction where an electrophile attacks a pi bond, resulting in the addition of atoms or groups to the molecule. The general mechanism for alkene + HX is:

Step 1: Formation of a carbocation intermediate (the rate-determining step).

Step 2: Nucleophilic attack by the halide ion on the carbocation.

The stability of the carbocation intermediate (tertiary > secondary > primary) dictates the major product.