Let Observations be

x₁, x₂, x₃, .........., x₁₆

$\therefore$       n = 16,  $\overline{x}$= 16

⇒        $16=\frac{x_1+x_2+\mathrm{......}+x_{16}}{16}$

⇒        x₁ + x₂ + ......... + x₁₆ = 256

Let x₁ = 16 (deleted)

⇒        (x₂ + x₃ + .......... + x₁₆) = 256 – 16 = 240

$\therefore$       New mean

$\frac{12+({\mathrm{x}}_2+{\mathrm{x}}_3+......+{\mathrm{x}}_{16})}{18}=\frac{12+240}{18}=\frac{252}{18}=14$