The mole fraction of a solvent in aqueous solution of a solute is 0.8. The molality (in mol kg

Engineering

Chemistry

Concentration Terms

Question

The mole fraction of a solvent in aqueous solution of a solute is 0.8. The molality (in mol kg^–1) of the aqueous solution is

13.88 × 10^–3

13.88 × 10^–1

13.88 × 10^–2

13.88

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X_solvent = 0.8 = 8/10

N_Total= 10, n_solutent = 8, n_solute = 2

Wt of solvent = 8 × 18

$Molality = \frac{2 \times 1000}{8 \times 18}$