Engineering
Chemistry
Mole and Its Calculation
Question

The number of carbon atoms present in a signature, if a signature written by carbon pencil weights 1.2 × 10–3 g is

3.01 × 1019

6.02 × 1020

12.04 × 1020

6.02 × 1019

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Solution

wC = 1.2 × 10–3
C-atom = nC × NA = 1.2 × 10–3 ×  × 6.02 × 1023
= 6.02 × 1019