Engineering
Physics
SHM of Simple Pendulum
Errors
Question

The period of oscillation of a simple pendulum is \(T = 2\pi\sqrt{\frac{L}{g}}\). Measured value of L is 20.0 cm known to 1 mm accuracy and time for 100 oscillations of the pendulum is found to be 90s using a wrist watch of 1s resolution. The accuracy in the determination of g is :

3%

1%

2%

5%

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Solution

Δgg=Δℓ+2ΔTT

=1×100200+2×190×100

=12+209=9+4018=4918=3%