The pressure inside two soap bubbles are 1.02 atm. and 1.03 atm. respectively. The ratio of their volumes is -

Engineering

Physics

Summation of Vectors

Surface Tension and Surface Energy

Calculus

Question

The pressure inside two soap bubbles are 1.02 atm. and 1.03 atm. respectively. The ratio of their volumes is -

102 : 103

27 : 8

(103)³ : (102)³

9 : 4

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$P_{in} - P_{atm} = excess pressure = \frac{4 T}{R}$

$∴ \frac{R_{1}}{R_{2}} = \frac{{ΔP}_{2}}{{ΔP}_{1}} = \frac{3}{2}$

$∴ \frac{V_{1}}{V_{2}} = \frac{R_{1}^{3}}{R_{2}^{3}} = \frac{27}{8}$