The probabilities of three mutually exclusive events A, B and C are given by , and . Then (PUBUC) is.

Engineering

Mathematics

Basic Definitions Related to Probability

Addition Theorem on Probability

Question

The probabilities of three mutually exclusive events A, B and C are given by $\frac{1}{3}, \frac{1}{4}$ , and $\frac{5}{12}$ . Then (PUBUC) is.

$\frac{9}{12}$

$\frac{11}{12}$

$\frac{7}{12}$

LiveFree JEE Main Previous Year Online Papers Live Free JEE Advance Previous Year Online Papers

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

Mutually exclusive events cannot occur simultaneously. The probability of their union is the sum of individual probabilities.

Given: P(A) = $\frac{1}{3}$ , P(B) = $\frac{1}{4}$ , P(C) = $\frac{5}{12}$ .

P(A∪B∪C) = P(A) + P(B) + P(C) = $\frac{1}{3}$ + $\frac{1}{4}$ + $\frac{5}{12}$ = $\frac{4}{12}$ + $\frac{3}{12}$ + $\frac{5}{12}$ = $\frac{12}{12}$ = 1.

Final Answer: 1