The probabilities of three mutually exclusive events A, B, C are .

Engineering

Mathematics

Conditional Probability

Question

The probabilities of three mutually exclusive events A, B, C are $P (A) = \frac{2}{3}, P (B) = \frac{1}{4}, P (C) = \frac{1}{6}$ .

True

False

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Since the events A, B, C are mutually exclusive, we have

P(A∪B∪C) = P(A) + P(B) + P(C
= 2 / 3 + 1 /4 + 1 / 6 = 13 / 12 < 1
which is impossible since the probability of any event cannot be greater than 1.

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