The probability of getting a number greater than 2 by throwing a fair dice is:

Engineering

Mathematics

Conditional Probability

Question

$\frac{2}{3}$

$\frac{1}{3}$

$\frac{3}{5}$

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S = { 1, 2, 3, 4, 5, 6 }

n(S) = 6

E = event of getting a number greater than 2.

∴ E = { 3, 4, 5, 6 } ⇒ n(E) = 4

Required prob = P(E) = $\frac{n (E)}{n (S)} = \frac{4}{6} = \frac{2}{3}$

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