The probability that exactly one of the independent events A and B occurs is equal to

Engineering

Mathematics

Conditional Probability

Question

P(A) + P(B) − 2P(A∩B)

P(A) + P(B) − P(A∩B)

$P (A) + P (B) - 2 P (A \cap B)$

None of the above

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

P (A \cap B) + P (B \cap A)

= P(A) − P(A∩B) + P(B) − P(A∩B)

= P(A) + P(B) − 2P(A∩B)

Also

P (A \cap B) + P (B \cap A)

= 1 - P (A) + 1 - P (B) - 2 {1 - P (A \cup B)}

= 1 - P (A) + 1 - P (B) - 2 {1 - P (A) - P (B) + P (A \cap B)}

= P (A) + P (B) - P (A \cap B)

Please subscribe our Youtube channel to unlock this solution.