This question involves finding the product of a chemical reaction. The given reactant is an alkene undergoing hydroboration-oxidation, which is a two-step reaction that adds water across the double bond in an anti-Markovnikov fashion and with syn addition (resulting in the same stereoisomer).

Step 1: Identify the Reaction
The reaction shown is hydroboration-oxidation. The first reagent, $B_{2} H_{6}$ (diborane), represents the hydroboration step. The second reagent, $H_{2} O_{2}, {OH}^{-}$ (hydrogen peroxide in a basic solution), represents the oxidation step.

Step 2: Understand the Regiochemistry and Stereochemistry
Hydroboration-oxidation has two key outcomes:

Regiochemistry (Orientation of Addition): The boron (B) and hydrogen (H) add across the carbon-carbon double bond. The boron atom attaches to the less substituted carbon, leading to the anti-Markovnikov product after oxidation replaces the boron with a hydroxyl group ( $OH$ ).
Stereochemistry (Spatial Arrangement): The addition of the B-H bond is a syn addition. This means the H and OH groups add to the same face of the alkene, resulting in a specific stereoisomer.

Step 3: Analyze the Reactant
The reactant is a cyclic alkene. The double bond is between carbons 1 and 2. Carbon 1 is more substituted (it is attached to two other carbons from the ring) than carbon 2 (which is attached to one carbon and one hydrogen). Therefore, according to anti-Markovnikov addition, the boron will add to carbon 2 and the hydrogen will add to carbon 1.

Step 4: Predict the Product
After the oxidation step, the boron is replaced by an OH group. Therefore, the final product will be an alcohol where the OH group is attached to the less substituted carbon (carbon 2). Because the reaction occurs with syn stereochemistry on a cyclic system, the two new groups (H and OH) will be cis to each other on the ring.

Final Answer:
The correct product is an alcohol with the OH group on the less substituted carbon, and the H and OH are cis to each other. This matches the structure in the second option.

Related Topics

Alkene Addition Reactions
Markovnikov's Rule
Syn and Anti Addition
Oxidation Reactions

Key Formulae and Theory

General Reaction:
$R - CH = CH 2 \overset{1. B_{2} H_{6}, THF 2. H_{2} O_{2}, {OH}^{-}}{\to} R - CH 2 - CH 2 OH$

Key Points:

Anti-Markovnikov addition of water.
Syn stereochemistry of addition.
No carbocation intermediate is formed; the mechanism involves a four-membered transition state.
The product is an alcohol.