The quantum number of four electrons are given below:I. n = 4, ℓ = 2, mℓ = –2, ms = II. n = 3, ℓ = 2, mℓ = 1, ms = III. n = 4, ℓ = 1, mℓ = 0, ms = IV. n = 3, ℓ = 1, mℓ = 1, ms = The correct order of their increasing energies will be

Engineering

Chemistry

Electronic Configuration

Quantum Numbers

Question

The quantum number of four electrons are given below:

I. n = 4, ℓ = 2, m_ℓ = –2, m_s = $- \frac{1}{2}$

II. n = 3, ℓ = 2, m_ℓ = 1, m_s = $+ \frac{1}{2}$

III. n = 4, ℓ = 1, m_ℓ = 0, m_s = $+ \frac{1}{2}$

IV. n = 3, ℓ = 1, m_ℓ = 1, m_s = $- \frac{1}{2}$

The correct order of their increasing energies will be

I < II < III < IV

IV < II < III < I

I < III < II < IV

IV < III < II < I

College PredictorLive

Know your College Admission Chances Based on your Rank/Percentile, Category and Home State.

Get your JEE Main Personalised Report with Top Predicted Colleges in JoSA

According to Aufbau principle, the energy sequence is 3p < 3d < 4p < 4d