Question
The reactions of Cl2 gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two (different) oxoacids of chlorine, P and Q, respectively. The Cl2 gas reacts with SO2 gas, in presence of charcoal, to give a product R. R reacts with while phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus, T.
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P and Q, respectively, are the sodium salts of
Cl2 + cold dil NaOH → NaCl + NaOCl (P)
Cl2 + hot conc. NaOH → NaCl + NaClO3 (Q)
NaOCl is salt of hypochlorous acid
NaClO3 is salt of chloric acid
Cl2 + SO2 → SO2Cl2 (R)
5SO2Cl2 + 5P4 → 2PCl5 (S) + 5SO2
PCl5 + 4H2O → H3PO4 (T) + 5HCl
R, S and T, respectively, are
Cl2 + cold dil NaOH → NaCl + NaOCl (P)
Cl2 + hot conc. NaOH → NaCl + NaClO3 (Q)
NaOCl is salt of hypochlorous acid
NaClO3 is salt of chloric acid
Cl2 + SO2 → SO2Cl2 (R)
5SO2Cl2 + 5P4 → 2PCl5 (S) + 5SO2
PCl5 + 4H2O → H3PO4 (T) + 5HCl