Engineering
Physics
Degree of Freedom Internal Energy of Gas and Specific Heat Capacity of Gases
Question

The specific heats, CP and CV of a gas of diatomic molecules, A, are given (in units of J mol–1 K–1) by 29 and 22, respectively. Another gas of diatomic molecules, B, has the corresponding values 30 and 21. If they are treated as ideal gases, then :

A has one vibrational mode and B has two         

Both A and B have a vibrational mode each

A is rigid but B has a vibrational mode   

A has a vibrational mode but B has none

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Solution

For A:

CpCv=γ=1+2f=2922

It gives f = 6.3 ≈ 6 (3 translational, 2 rotational and 1 vibrational)

For B:

CpCv=γ=1+2f=3021

⇒ f = 4.67

⇒ ≈ 5 (3 translational, 2 rotational, no vibrational)