Engineering
Chemistry
Enthalpy of Formation Combustion and Bond
Question

The standard enthalpies of formation of CO2(g), H2O(l) and glucose(s) at 25°C are – 400 kJ/mol, – 300 kJ/mol and –1300 kJ/mol, respectively. The standard enthalpy of combustion per gram of glucose at 25°C is :

– 16.11 kJ

–2900 kJ

+ 16.11 kJ

+ 2900 kJ

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Solution

C6H12O6(s) + 6O2(g)  6CO2(g) + 6H2O (l)

 ΔHcomb.C6H12O6°=6ΔHfCO2°+6ΔHfH2O()°ΔHfC6H12O6(s)°

= 6 × (– 400) + 6 × (– 300) – (– 1300)

= – 2900 kJ/mol

  Standard enthalpy of combustion per gram of glucose =  2900180  = – 16.11 kJ