The standard Gibbs energy change at 300 K for the reaction 2A ⇌ B + C is 2494.2 J. At a given time, the composition of the reaction mixture is , [B] = 2 and . The reaction proceeds in the: [R = 8.314 J/K/mol, e = 2.718]

Engineering

Chemistry

Gibbs Free Energy and Equilibrium

Question

The standard Gibbs energy change at 300 K for the reaction

2A ⇌ B + C is 2494.2 J.

At a given time, the composition of the reaction mixture is $[A] = \frac{1}{2}$ , [B] = 2 and $[C] = \frac{1}{2}$ . The reaction proceeds in the: [R = 8.314 J/K/mol, e = 2.718]

reverse direction because Q > K_C

forward direction because Q < K_C

forward direction because Q > K_C

reverse direction because Q < K_C

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(D) $∆$ G° = – RT ℓn K

2494.2 = – 8.314 × 300 ln K

$ℓn K = - 1 = ℓn \frac{1}{e}$

$K = \frac{1}{e}$

$θ = \frac{{[B]}_{t} {[C]}_{t}}{{[A]}_{t}^{2}} = \frac{2 \times \frac{1}{2}}{{(\frac{1}{2})}^{2}} = 4$

$θ$ > K ⇒ (4)