The substituents R1 and R2 for nine peptides are listed in the table given below. How many of these peptides are positively charged at pH = 7.0 ?

| Peptide | R1 | R2 |
| I | H | H |
| II | H | CH3 |
| III | CH2COOH | H |
| IV | CH2CONH2 | (CH2)4 NH2 |
| V | CH2CONH2 | CH2CONH2 |
| VI | (CH2)4 NH2 | (CH2)4 NH2 |
| VII | CH2COOH | CH2CONH2 |
| VIII | CH2OH | (CH2)4 NH2 |
| IX | (CH2)4 NH2 | CH3 |
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Any amino acid will exist in a cationic form in solution of pH < pI (isoelectric point)
pH = 7 is less than pI given which implies pI > 7 basic amino acid.
Given peptide will have basic nature if number of basic sites are greater than acidic sites.
Peptide IV R1 = CH2CONH2 R2 = (CH2)4NH2
Peptide VI R1 = (CH2)4NH2 R2 = (CH2)4NH2
Peptide VIII R1 = CH2OH R2 = (CH2)4NH2
peptide IX R1 = (CH2)4NH2 R2 = CH3