The sum of first 16 terms of the AP 10, 6, 2, ..... is

Foundation

Mathematics Foundation

Sum of n terms of an AP

Question

320

– 320

– 400

– 352

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$l$ = T₁₆ = 10 + 15 × (–4) = – 50.

$∴ sum = \frac{n}{2} (a + ℓ) = \frac{16}{2} (10 - 50) = 8 \times (- 40) = - 320 .$