The sum of first 40 positive integers divisible by 6 is

Foundation

Mathematics Foundation

Sum of n terms of an AP

Question

The sum of first 40 positive integers divisible by 6 is

A

4920

B

2460

C

3640

D

4860

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Required sum $= 6 + 12 + 18 + . ... + 240 = \frac{40}{2} (6 + 240) = 4920 .$