The sum of first n terms of an AP is (3n2 + 6n). The common difference of the AP is
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Given Sn = (3n2 + 6n).
T1 = S1 = (3 × 12 + 6 × 1) = 9, S2 = (3 × 22 + 6 × 2) = 24.
T2 = (S2 – S1) = (24 – 9) = 15.
Hence, d = (T2 – T1) = 15 – 9 = 6.